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* Output result of source block to a file
@ 2019-06-05 10:41 Roger Mason
  2019-06-05 13:17 ` stardiviner
  2019-06-05 13:33 ` Ken Mankoff
  0 siblings, 2 replies; 12+ messages in thread
From: Roger Mason @ 2019-06-05 10:41 UTC (permalink / raw)
  To: Org-Mode

Hello,

I want to output the result of the evaluation of a (python) source block
to a (graphics) file and have a link to the file inserted in the buffer.

Here is the code:

#+begin_src python :results value file :file scaleplot02.pdf :exports results :var data=test
  import matplotlib.pyplot as plt
  import csv

  scale = []
  lescale = []
  cdscale = []

  energy = []
  leenergy = []
  cdenergy = []

  for row in data:
      scale.append(float(row[0]))
      energy.append(float(row[1]))
      if int(row[2]) != 0:
	 lescale.append(float(row[0]))
	 leenergy.append(float(row[1]))
      if int(row[3]) != 0:
	 cdscale.append(float(row[0]))
	 cdenergy.append(float(row[1]))        

  plt.plot(scale,energy, 'r+')
  plt.plot(lescale,leenergy, 'go')
  plt.plot(cdscale,cdenergy, 'bo')
  plt.xlabel('scale')
  plt.ylabel('energy (Ha)')
  plt.title('Energy vs scale')
  plt.legend()
  plt.savefig(file)
  print ("[[./%s]]" % file)
#+end_src

This is the error:

NameError: name 'file' is not defined

Obviously the syntax on the begin_src line is wrong, but what should it
be instead?

Thanks,
Roger

^ permalink raw reply	[flat|nested] 12+ messages in thread

• * Re: Output result of source block to a file
    2019-06-05 10:41 Output result of source block to a file Roger Mason
  @ 2019-06-05 13:17 ` stardiviner
    2019-06-06 11:36   ` Roger Mason
    2019-06-06 18:04   ` Roger Mason
    2019-06-05 13:33 ` Ken Mankoff
    1 sibling, 2 replies; 12+ messages in thread
  From: stardiviner @ 2019-06-05 13:17 UTC (permalink / raw)
    To: emacs-orgmode
  
  
  Roger Mason <rmason@mun.ca> writes:
  
  > Hello,
  >
  > I want to output the result of the evaluation of a (python) source block
  > to a (graphics) file and have a link to the file inserted in the buffer.
  
  For this, you should try updated header arguments like ":results graphics link"
  or ":results file link".
  
  >
  > Here is the code:
  >
  > #+begin_src python :results value file :file scaleplot02.pdf :exports results :var data=test
  >   import matplotlib.pyplot as plt
  >   import csv
  >
  >   scale = []
  >   lescale = []
  >   cdscale = []
  >
  >   energy = []
  >   leenergy = []
  >   cdenergy = []
  >
  >   for row in data:
  >       scale.append(float(row[0]))
  >       energy.append(float(row[1]))
  >       if int(row[2]) != 0:
  > 	 lescale.append(float(row[0]))
  > 	 leenergy.append(float(row[1]))
  >       if int(row[3]) != 0:
  > 	 cdscale.append(float(row[0]))
  > 	 cdenergy.append(float(row[1]))        
  >
  >   plt.plot(scale,energy, 'r+')
  >   plt.plot(lescale,leenergy, 'go')
  >   plt.plot(cdscale,cdenergy, 'bo')
  >   plt.xlabel('scale')
  >   plt.ylabel('energy (Ha)')
  >   plt.title('Energy vs scale')
  >   plt.legend()
  >   plt.savefig(file)
  >   print ("[[./%s]]" % file)
  > #+end_src
  >
  > This is the error:
  >
  > NameError: name 'file' is not defined
  >
  > Obviously the syntax on the begin_src line is wrong, but what should it
  > be instead?
  >
  > Thanks,
  > Roger
  
  
  -- 
  [ stardiviner ]
         I try to make every word tell the meaning what I want to express.
  
         Blog: https://stardiviner.github.io/
         IRC(freenode): stardiviner, Matrix: stardiviner
         GPG: F09F650D7D674819892591401B5DF1C95AE89AC3
        
  
  ^ permalink raw reply	[flat|nested] 12+ messages in thread

• • * Re: Output result of source block to a file
      2019-06-05 13:17 ` stardiviner
    @ 2019-06-06 11:36   ` Roger Mason
      2019-06-07 11:05     ` stardiviner
      2019-06-06 18:04   ` Roger Mason
      1 sibling, 1 reply; 12+ messages in thread
    From: Roger Mason @ 2019-06-06 11:36 UTC (permalink / raw)
      To: numbchild; +Cc: emacs-orgmode
    
    Hello,
    
    stardiviner <numbchild@gmail.com> writes:
    
    > Roger Mason <rmason@mun.ca> writes:
    >
    >> Hello,
    >>
    >> I want to output the result of the evaluation of a (python) source block
    >> to a (graphics) file and have a link to the file inserted in the buffer.
    
    >> #+begin_src python :results value file :file scaleplot02.pdf :exports results :var data=test
    
    ...snip...
    
    >>   plt.savefig(file)
    >>   print ("[[./%s]]" % file)
    >> #+end_src
    
    > For this, you should try updated header arguments like ":results graphics link"
    > or ":results file link".
    
    Thanks for your reply.
    
    The current incarnation:
    
    #+begin_src python :results graphics link :exports results :var data=test :var file="scaleplot2.pdf"
    
    The output:
    #+RESULTS: scaleplot02
    : None
    
    I'm guessing I have the syntax wrong.  Is it documented somewhere?  I'm
    on Org mode version 9.1.13 (release_9.1.13-784-ged7d1d @
    /home/rmason/.emacs.d/org-git/lisp/).
    
    Cheers,
    Roger
    
    ^ permalink raw reply	[flat|nested] 12+ messages in thread

  • • * Re: Output result of source block to a file
        2019-06-06 11:36   ` Roger Mason
      @ 2019-06-07 11:05     ` stardiviner
        0 siblings, 0 replies; 12+ messages in thread
      From: stardiviner @ 2019-06-07 11:05 UTC (permalink / raw)
        To: Roger Mason; +Cc: emacs-orgmode
      
      
      Roger Mason <rmason@mun.ca> writes:
      
      > Hello,
      >
      > stardiviner <numbchild@gmail.com> writes:
      >
      >> Roger Mason <rmason@mun.ca> writes:
      >>
      >>> Hello,
      >>>
      >>> I want to output the result of the evaluation of a (python) source block
      >>> to a (graphics) file and have a link to the file inserted in the buffer.
      >
      >>> #+begin_src python :results value file :file scaleplot02.pdf :exports results :var data=test
      >
      > ...snip...
      >
      >>>   plt.savefig(file)
      >>>   print ("[[./%s]]" % file)
      >>> #+end_src
      >
      >> For this, you should try updated header arguments like ":results graphics link"
      >> or ":results file link".
      >
      > Thanks for your reply.
      >
      > The current incarnation:
      >
      > #+begin_src python :results graphics link :exports results :var data=test :var file="scaleplot2.pdf"
      >
      > The output:
      > #+RESULTS: scaleplot02
      > : None
      >
      
      First, check out =org-manual.org= documentation.
      And you don't need ~print ("[[./%s]]" % file)~ in Python code if you use ~:results graphics link~.
      
      > I'm guessing I have the syntax wrong.  Is it documented somewhere?  I'm
      > on Org mode version 9.1.13 (release_9.1.13-784-ged7d1d @
      > /home/rmason/.emacs.d/org-git/lisp/).
      >
      > Cheers,
      > Roger
      
      
      -- 
      [ stardiviner ]
             I try to make every word tell the meaning what I want to express.
      
             Blog: https://stardiviner.github.io/
             IRC(freenode): stardiviner, Matrix: stardiviner
             GPG: F09F650D7D674819892591401B5DF1C95AE89AC3
            
      
      ^ permalink raw reply	[flat|nested] 12+ messages in thread

  • * Re: Output result of source block to a file
      2019-06-05 13:17 ` stardiviner
      2019-06-06 11:36   ` Roger Mason
    @ 2019-06-06 18:04   ` Roger Mason
      2019-06-06 21:12     ` John Kitchin
      1 sibling, 1 reply; 12+ messages in thread
    From: Roger Mason @ 2019-06-06 18:04 UTC (permalink / raw)
      To: numbchild; +Cc: emacs-orgmode
    
    Hello again,
    
    stardiviner <numbchild@gmail.com> writes:
    
    > Roger Mason <rmason@mun.ca> writes:
    >
    >> Hello,
    >>
    >> I want to output the result of the evaluation of a (python) source block
    >> to a (graphics) file and have a link to the file inserted in the buffer.
    >
    > For this, you should try updated header arguments like ":results graphics link"
    > or ":results file link".
    
    I updated to Org mode version 9.2.3 (release_9.2.3-390-gfb5091 @ /home/rmason/.emacs.d/org-git/lisp/)
    
    This works but sets the results to verbatim, hence the exported &
    compiled code does not include the graphic.
    
    #+name: scaleplot03
    #+begin_src python :results output graphics link :exports results :var data=test :var file="scaleplot03.pdf"
      import matplotlib.pyplot as plt
      import csv
    
      scale = []
      lescale = []
      cdscale = []
    
      energy = []
      leenergy = []
      cdenergy = []
    
      for row in data:
          scale.append(float(row[0]))
          energy.append(float(row[1]))
          if int(row[2]) != 0:
                 lescale.append(float(row[0]))
                 leenergy.append(float(row[1]))
          if int(row[3]) != 0:
                 cdscale.append(float(row[0]))
                 cdenergy.append(float(row[1]))        
    
      plt.plot(scale,energy, 'r+')
      plt.plot(lescale,leenergy, 'go')
      plt.plot(cdscale,cdenergy, 'bo')
      plt.xlabel('scale')
      plt.ylabel('energy (Ha)')
      plt.title('Energy vs scale')
      plt.legend()
      plt.savefig(file)
      print ("./%s" % file)
    #+end_src
    
    #+RESULTS: scaleplot03
    : ./scaleplot03.pdf
    
    This header does not work either:
    #+name: scaleplot04
    #+begin_src python :results file link :exports results :var data=test :var file="scaleplot04.pdf"
    ( same pythone code here)
    
    #+RESULTS: scaleplot04
    [[file:None]]
    ]]
    #+end_src
    
    Thank you for your help.
    
    Roger
    
    ^ permalink raw reply	[flat|nested] 12+ messages in thread

  • • * Re: Output result of source block to a file
        2019-06-06 18:04   ` Roger Mason
      @ 2019-06-06 21:12     ` John Kitchin
        2019-06-07 10:00       ` Roger Mason
        0 siblings, 1 reply; 12+ messages in thread
      From: John Kitchin @ 2019-06-06 21:12 UTC (permalink / raw)
        To: Roger Mason; +Cc: org-mode-email
      
      [-- Attachment #1: Type: text/plain, Size: 2427 bytes --]
      
      I think you can use something like this:
      
      #+BEGIN_SRC python :results output file :var fname="test.png"
      import matplotlib.pyplot as plt
      import io
      
      f = io.StringIO()
      plt.plot([1, 2, 3, 17])
      plt.savefig(fname)
      print(fname, end='')
      #+END_SRC
      
      It is in Python3.
      
      John
      
      -----------------------------------
      Professor John Kitchin
      Doherty Hall A207F
      Department of Chemical Engineering
      Carnegie Mellon University
      Pittsburgh, PA 15213
      412-268-7803
      @johnkitchin
      http://kitchingroup.cheme.cmu.edu
      
      
      
      On Thu, Jun 6, 2019 at 2:27 PM Roger Mason <rmason@mun.ca> wrote:
      
      > Hello again,
      >
      > stardiviner <numbchild@gmail.com> writes:
      >
      > > Roger Mason <rmason@mun.ca> writes:
      > >
      > >> Hello,
      > >>
      > >> I want to output the result of the evaluation of a (python) source block
      > >> to a (graphics) file and have a link to the file inserted in the buffer.
      > >
      > > For this, you should try updated header arguments like ":results
      > graphics link"
      > > or ":results file link".
      >
      > I updated to Org mode version 9.2.3 (release_9.2.3-390-gfb5091 @
      > /home/rmason/.emacs.d/org-git/lisp/)
      >
      > This works but sets the results to verbatim, hence the exported &
      > compiled code does not include the graphic.
      >
      > #+name: scaleplot03
      > #+begin_src python :results output graphics link :exports results :var
      > data=test :var file="scaleplot03.pdf"
      >   import matplotlib.pyplot as plt
      >   import csv
      >
      >   scale = []
      >   lescale = []
      >   cdscale = []
      >
      >   energy = []
      >   leenergy = []
      >   cdenergy = []
      >
      >   for row in data:
      >       scale.append(float(row[0]))
      >       energy.append(float(row[1]))
      >       if int(row[2]) != 0:
      >              lescale.append(float(row[0]))
      >              leenergy.append(float(row[1]))
      >       if int(row[3]) != 0:
      >              cdscale.append(float(row[0]))
      >              cdenergy.append(float(row[1]))
      >
      >   plt.plot(scale,energy, 'r+')
      >   plt.plot(lescale,leenergy, 'go')
      >   plt.plot(cdscale,cdenergy, 'bo')
      >   plt.xlabel('scale')
      >   plt.ylabel('energy (Ha)')
      >   plt.title('Energy vs scale')
      >   plt.legend()
      >   plt.savefig(file)
      >   print ("./%s" % file)
      > #+end_src
      >
      > #+RESULTS: scaleplot03
      > : ./scaleplot03.pdf
      >
      > This header does not work either:
      > #+name: scaleplot04
      > #+begin_src python :results file link :exports results :var data=test :var
      > file="scaleplot04.pdf"
      > ( same pythone code here)
      >
      > #+RESULTS: scaleplot04
      > [[file:None]]
      > ]]
      > #+end_src
      >
      > Thank you for your help.
      >
      > Roger
      >
      >
      >
      >
      
      [-- Attachment #2: Type: text/html, Size: 3633 bytes --]
      
      ^ permalink raw reply	[flat|nested] 12+ messages in thread

    • • * Re: Output result of source block to a file
          2019-06-06 21:12     ` John Kitchin
        @ 2019-06-07 10:00       ` Roger Mason
          2019-06-07 15:01         ` John Kitchin
          0 siblings, 1 reply; 12+ messages in thread
        From: Roger Mason @ 2019-06-07 10:00 UTC (permalink / raw)
          To: John Kitchin; +Cc: Roger Mason, org-mode-email
        
        Hello John,
        
        John Kitchin <jkitchin@andrew.cmu.edu> writes:
        
        > I think you can use something like this:
        >
        > #+BEGIN_SRC python :results output file :var fname="test.png"
        > import matplotlib.pyplot as plt
        > import io
        >
        > f = io.StringIO()
        > plt.plot([1, 2, 3, 17])
        > plt.savefig(fname)
        > print(fname, end='')
        > #+END_SRC
        >
        > It is in Python3.
        
        Thank you.  That works.
        
        Best wishes,
        Roger
        
        ^ permalink raw reply	[flat|nested] 12+ messages in thread

      • • * Re: Output result of source block to a file
            2019-06-07 10:00       ` Roger Mason
          @ 2019-06-07 15:01         ` John Kitchin
            2019-06-08 10:51           ` Roger Mason
            0 siblings, 1 reply; 12+ messages in thread
          From: John Kitchin @ 2019-06-07 15:01 UTC (permalink / raw)
            To: Roger Mason; +Cc: org-mode-email
          
          you probably figured out the "import io" and "f = io..." line are not
          necessary here.
          
          I couldn't figure out a reasonable way to use :results graphics link
          that didn't result in repeating the filename more than desired. These
          also both work, but seem to both require repeating the filename twice.
          
          #+BEGIN_SRC python :results graphics link :var fname="test.png" :file "test.png"
          import matplotlib.pyplot as plt
          
          plt.plot([1, 2, 3, 1])
          plt.savefig(fname)
          #+END_SRC
          
          #+BEGIN_SRC python :results graphics link :file "test.png"
          import matplotlib.pyplot as plt
          
          plt.plot([1, 2, 3])
          plt.savefig("test.png")
          #+END_SRC
          
          Something like this should work, but there seem to be some extra bytes
          getting put in the png file from the decoding, and latin-1 is the only
          one I can get to work. If anyone knows how to get this to work, I am
          interested in seeing it!
          
          #+BEGIN_SRC python :results value :file "io.png"
          import matplotlib.pyplot as plt
          import io
          buf = io.BytesIO()
          
          plt.plot([1, 2, 3])
          plt.savefig(buf, format='png')
          
          s = buf.getvalue()
          return s.decode('latin-1')
          #+END_SRC
          
          
          In general though, all of these are much more work than using
          ob-ipython, which just puts images in the buffer for you.
          
          Roger Mason <rmason@mun.ca> writes:
          
          > Hello John,
          >
          > John Kitchin <jkitchin@andrew.cmu.edu> writes:
          >
          >> I think you can use something like this:
          >>
          >> #+BEGIN_SRC python :results output file :var fname="test.png"
          >> import matplotlib.pyplot as plt
          >> import io
          >>
          >> f = io.StringIO()
          >> plt.plot([1, 2, 3, 17])
          >> plt.savefig(fname)
          >> print(fname, end='')
          >> #+END_SRC
          >>
          >> It is in Python3.
          >
          > Thank you.  That works.
          >
          > Best wishes,
          > Roger
          
          
          --
          Professor John Kitchin
          Doherty Hall A207F
          Department of Chemical Engineering
          Carnegie Mellon University
          Pittsburgh, PA 15213
          412-268-7803
          @johnkitchin
          http://kitchingroup.cheme.cmu.edu
          
          ^ permalink raw reply	[flat|nested] 12+ messages in thread

        • • * Re: Output result of source block to a file
              2019-06-07 15:01         ` John Kitchin
            @ 2019-06-08 10:51           ` Roger Mason
              2019-06-08 20:40             ` John Kitchin
              0 siblings, 1 reply; 12+ messages in thread
            From: Roger Mason @ 2019-06-08 10:51 UTC (permalink / raw)
              To: John Kitchin; +Cc: Roger Mason, org-mode-email
            
            Hello John,
            
            John Kitchin <jkitchin@andrew.cmu.edu> writes:
            
            > you probably figured out the "import io" and "f = io..." line are not
            > necessary here.
            
            Indeed.
            
            > I couldn't figure out a reasonable way to use :results graphics link
            > that didn't result in repeating the filename more than desired. These
            > also both work, but seem to both require repeating the filename twice.
            >
            > #+BEGIN_SRC python :results graphics link :var fname="test.png" :file "test.png"
            > import matplotlib.pyplot as plt
            >
            > plt.plot([1, 2, 3, 1])
            > plt.savefig(fname)
            > #+END_SRC
            >
            > #+BEGIN_SRC python :results graphics link :file "test.png"
            > import matplotlib.pyplot as plt
            >
            > plt.plot([1, 2, 3])
            > plt.savefig("test.png")
            > #+END_SRC
            >
            > Something like this should work, but there seem to be some extra bytes
            > getting put in the png file from the decoding, and latin-1 is the only
            > one I can get to work. If anyone knows how to get this to work, I am
            > interested in seeing it!
            >
            > #+BEGIN_SRC python :results value :file "io.png"
            > import matplotlib.pyplot as plt
            > import io
            > buf = io.BytesIO()
            >
            > plt.plot([1, 2, 3])
            > plt.savefig(buf, format='png')
            >
            > s = buf.getvalue()
            > return s.decode('latin-1')
            > #+END_SRC
            >
            >
            > In general though, all of these are much more work than using
            > ob-ipython, which just puts images in the buffer for you.
            
            I will investigate that, thanks for the tip.  I began this bit of work
            using gnuplot for making x-y plots, but I find that gnuplot syntax gets
            messy for anything but simple data.  I am not a particular fan
            of python so I'm also looking into guile & racket for plotting.
            
            Thanks for your help, it is much appreciated.
            
            Roger
            
            ^ permalink raw reply	[flat|nested] 12+ messages in thread

          • • * Re: Output result of source block to a file
                2019-06-08 10:51           ` Roger Mason
              @ 2019-06-08 20:40             ` John Kitchin
                0 siblings, 0 replies; 12+ messages in thread
              From: John Kitchin @ 2019-06-08 20:40 UTC (permalink / raw)
                To: Roger Mason; +Cc: org-mode-email
              
              [-- Attachment #1: Type: text/plain, Size: 2394 bytes --]
              
              A similar approach as the last one should work, the problem I was having is
              that to print the binary string from python you have to decode it, and
              latin-1 seems close to right, but it puts a bunch of extra bytes in it that
              lead to a bad png file. I feel like this worked in Python2 with StringIO,
              but not in Python3 with BytesIO.
              
              
              
              John
              
              -----------------------------------
              Professor John Kitchin
              Doherty Hall A207F
              Department of Chemical Engineering
              Carnegie Mellon University
              Pittsburgh, PA 15213
              412-268-7803
              @johnkitchin
              http://kitchingroup.cheme.cmu.edu
              
              
              
              On Sat, Jun 8, 2019 at 6:52 AM Roger Mason <rmason@mun.ca> wrote:
              
              > Hello John,
              >
              > John Kitchin <jkitchin@andrew.cmu.edu> writes:
              >
              > > you probably figured out the "import io" and "f = io..." line are not
              > > necessary here.
              >
              > Indeed.
              >
              > > I couldn't figure out a reasonable way to use :results graphics link
              > > that didn't result in repeating the filename more than desired. These
              > > also both work, but seem to both require repeating the filename twice.
              > >
              > > #+BEGIN_SRC python :results graphics link :var fname="test.png" :file
              > "test.png"
              > > import matplotlib.pyplot as plt
              > >
              > > plt.plot([1, 2, 3, 1])
              > > plt.savefig(fname)
              > > #+END_SRC
              > >
              > > #+BEGIN_SRC python :results graphics link :file "test.png"
              > > import matplotlib.pyplot as plt
              > >
              > > plt.plot([1, 2, 3])
              > > plt.savefig("test.png")
              > > #+END_SRC
              > >
              > > Something like this should work, but there seem to be some extra bytes
              > > getting put in the png file from the decoding, and latin-1 is the only
              > > one I can get to work. If anyone knows how to get this to work, I am
              > > interested in seeing it!
              > >
              > > #+BEGIN_SRC python :results value :file "io.png"
              > > import matplotlib.pyplot as plt
              > > import io
              > > buf = io.BytesIO()
              > >
              > > plt.plot([1, 2, 3])
              > > plt.savefig(buf, format='png')
              > >
              > > s = buf.getvalue()
              > > return s.decode('latin-1')
              > > #+END_SRC
              > >
              > >
              > > In general though, all of these are much more work than using
              > > ob-ipython, which just puts images in the buffer for you.
              >
              > I will investigate that, thanks for the tip.  I began this bit of work
              > using gnuplot for making x-y plots, but I find that gnuplot syntax gets
              > messy for anything but simple data.  I am not a particular fan
              > of python so I'm also looking into guile & racket for plotting.
              >
              > Thanks for your help, it is much appreciated.
              >
              > Roger
              >
              
              [-- Attachment #2: Type: text/html, Size: 3447 bytes --]
              
              ^ permalink raw reply	[flat|nested] 12+ messages in thread

• * Re: Output result of source block to a file
    2019-06-05 10:41 Output result of source block to a file Roger Mason
    2019-06-05 13:17 ` stardiviner
  @ 2019-06-05 13:33 ` Ken Mankoff
    2019-06-06 11:48   ` Roger Mason
    1 sibling, 1 reply; 12+ messages in thread
  From: Ken Mankoff @ 2019-06-05 13:33 UTC (permalink / raw)
    To: Roger Mason; +Cc: Org-Mode
  
  
  On 2019-06-05 at 12:41 +02, Roger Mason <rmason@mun.ca> wrote...
  > I want to output the result of the evaluation of a (python) source
  > block to a (graphics) file and have a link to the file inserted in the
  > buffer.
  >
  > Here is the code:
  >
  > #+begin_src python :results value file :file scaleplot02.pdf :exports results :var data=test
  >   print ("[[./%s]]" % file)
  > #+end_src
  
  What about :var file="scaleplot02.pdf".
  
    -k.
  
  ^ permalink raw reply	[flat|nested] 12+ messages in thread

• • * Re: Output result of source block to a file
      2019-06-05 13:33 ` Ken Mankoff
    @ 2019-06-06 11:48   ` Roger Mason
      0 siblings, 0 replies; 12+ messages in thread
    From: Roger Mason @ 2019-06-06 11:48 UTC (permalink / raw)
      To: Ken Mankoff; +Cc: Roger Mason, Org-Mode
    
    Hello,
    Ken Mankoff <mankoff@gmail.com> writes:
    
    >
    > What about :var file="scaleplot02.pdf".
    
    That was my starting point, but the resulting link is prefixed by ':'
    
    Perhaps I should upgrade org.
    
    Cheers,
    Roger
    
    ^ permalink raw reply	[flat|nested] 12+ messages in thread

end of thread, other threads:[~2019-06-08 20:41 UTC | newest]

Thread overview: 12+ messages (download: mbox.gz / follow: Atom feed)
-- links below jump to the message on this page --
2019-06-05 10:41 Output result of source block to a file Roger Mason
2019-06-05 13:17 ` stardiviner
2019-06-06 11:36   ` Roger Mason
2019-06-07 11:05     ` stardiviner
2019-06-06 18:04   ` Roger Mason
2019-06-06 21:12     ` John Kitchin
2019-06-07 10:00       ` Roger Mason
2019-06-07 15:01         ` John Kitchin
2019-06-08 10:51           ` Roger Mason
2019-06-08 20:40             ` John Kitchin
2019-06-05 13:33 ` Ken Mankoff
2019-06-06 11:48   ` Roger Mason

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