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From: Cecil Westerhof <CecilWesterhof@xs4all.nl>
To: org-mode <emacs-orgmode@gnu.org>
Subject: Re: Making a list to string
Date: Thu, 12 Jul 2007 08:10:40 +0200	[thread overview]
Message-ID: <1184220640.6283.185.camel@Barebusta.DecebalComp> (raw)
In-Reply-To: <b71b18520707112304v25c2a570se0f0f49d4ed4a174@mail.gmail.com>

Op do, 12-07-2007 te 01:04 -0500, schreef Eddward DeVilla:
> On 7/12/07, Cecil Westerhof <CecilWesterhof@xs4all.nl> wrote:
> > Yes, it looks like it works completly. (What I am missing is a knowledge
> > of Lisp. Thus that will come.)
> >
> > One thing bugs me. I am used to end a formula ending with ';N'.
> 
> By default the field values are passed to the lisp expression as a
> string.  If you want it to be passed as a number you need the ;N.  So
> if @3$4 = 123:
> 
> '(foo @3$4)  => '(foo "123")
> '(foo @3$4);N => '(foo 123)

I remember Carsten mentioning something about this.
I would expect the ';N' have influence on the output, not on the input.

-- 
Cecil Westerhof <CecilWesterhof@xs4all.nl>

  reply	other threads:[~2007-07-12  6:10 UTC|newest]

Thread overview: 7+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2007-07-11 20:43 Making a list to string Cecil Westerhof
2007-07-11 21:54 ` Eddward DeVilla
2007-07-11 21:59   ` Eddward DeVilla
2007-07-12  5:23     ` Cecil Westerhof
2007-07-12  6:04       ` Eddward DeVilla
2007-07-12  6:10         ` Cecil Westerhof [this message]
2007-07-13 13:47       ` Carsten Dominik

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