Re: How do I specify the language for a :results code block

[Alan Schmitt <alan.schmitt@polytechnique.org>]

tsd@tsdye.com writes:

> Alan Schmitt <alan.schmitt@polytechnique.org> writes:
>
>> I tried this alternate approach, to directly generate the block:
>>
>> #+name: fetchcoq2
>> #+BEGIN_SRC sh :exports none :results raw :var f="demo.v"
>> echo "#+BEGIN_SRC coq"
>> head $f
>> echo
>> echo "#+END_SRC"
>> #+END_SRC
>>
>> #+call: fetchcoq2("demo.v")
>>
>> But then I get a result like this, with extra quoting:
>>
>> #+RESULTS:
>> : #+BEGIN_SRC coq
>> : Definition toto : forall x, exists y, x = y.
>> : 
>> : Lemma foo: forall x, x=x.
>> : #+END_SRC
>>
>> I feel like I'm missing something obvious. ":results code" is exactly
>> what I want (put the results in a SRC block), but I don't know how to
>> specify the headers of the generated code block.
>
> You need :results raw at the end of the call line.
>
> #+name: fetchcoq2
> #+BEGIN_SRC sh :exports none :results raw :var f="demo.v"
> echo "#+BEGIN_SRC coq"
> echo $f
> echo "#+END_SRC"
> #+END_SRC
>
> #+results: fetchcoq2
> #+BEGIN_SRC coq
> demo.v
> #+END_SRC
>
> #+call: fetchcoq2("demo.v") :results raw
>
> #+results:
> #+BEGIN_SRC coq
> demo.v
> #+END_SRC

Thanks, this is helping me much.

There are still one thing that I don't understand: I cannot make this
work when I have already evaluated the call in the buffer. More
precisely, if I have the following:

--8<---------------cut here---------------start------------->8---
#+name: fetchcoq
#+BEGIN_SRC sh :exports none :results raw :var f="foo.v"
echo "#+BEGIN_SRC coq"
head $f
echo
echo "#+END_SRC"
#+END_SRC

#+call: fetchcoq(f="demo.v") :results raw
--8<---------------cut here---------------end--------------->8---

when I evaluate the call line, I get this (as expected):

--8<---------------cut here---------------start------------->8---
#+name: fetchcoq
#+BEGIN_SRC sh :exports none :results raw :var f="foo.v"
echo "#+BEGIN_SRC coq"
head $f
echo
echo "#+END_SRC"
#+END_SRC

#+call: fetchcoq(f="demo.v") :results raw

#+RESULTS:
#+BEGIN_SRC coq
Definition toto : forall x, exists y, x = y.

Lemma foo: forall x, x=x.
#+END_SRC
--8<---------------cut here---------------end--------------->8---

Unfortunately, if I export this, the code is duplicated. Here is the
generated html, for instance:

,----
| <pre class="src src-coq"><span style="color: #FBDE2D;">Definition</span> <span style="color: #ff1493;">toto</span> : <span style="color: #D8FA3C;">forall</span> <span style="color: #D8FA3C;">x</span>, <span style="color: #9370db;">exists</span> y, x = y.
| 
| <span style="color: #FBDE2D;">Lemma</span> <span style="color: #ff1493;">foo</span>: <span style="color: #D8FA3C;">forall</span> <span style="color: #D8FA3C;">x</span>, x=x.
| #+END_SRC#+BEGIN_SRC coq
| <span style="color: #FBDE2D;">Definition</span> <span style="color: #ff1493;">toto</span> : <span style="color: #D8FA3C;">forall</span> <span style="color: #D8FA3C;">x</span>, <span style="color: #9370db;">exists</span> y, x = y.
| 
| <span style="color: #FBDE2D;">Lemma</span> <span style="color: #ff1493;">foo</span>: <span style="color: #D8FA3C;">forall</span> <span style="color: #D8FA3C;">x</span>, x=x.
| </pre>
`----

Exporting if the result is not in the buffer is fine. I tried adding a
":results replace" as inner header argument to the call line and to the
fetchcoq block, but it does not change anything.

How can I tell the call line to replace the results when exporting?

Thanks,

Alan