Re: How do I chain babel blocks with arguments?

[Alan Schmitt <alan.schmitt@polytechnique.org>]

Hi Eric,

On 2014-04-22 13:30, Eric Schulte <schulte.eric@gmail.com> writes:

> Sorry, that's because the "x" should be "z".  See the following.
>
> #+name: z
> : "bar"
> #+name: test3
> #+begin_src emacs-lisp :var x="foo"
> x
> #+end_src
>
> #+RESULTS: test3
> : foo
>
> #+name:test4
> #+begin_src emacs-lisp :var y=test3(x=z)
> y
> #+end_src
>
> #+results: test4
> : "bar"
>
> #+call: test4(y="BAZ")
>
> #+RESULTS:
> : BAZ

I'm afraid I'm not being clear: I want to use the result of `test3' in
the computation done to test4. Intuitively, I want test4 to be something
like: "(lambda (x) (... (test3 x) ...))". This is why I was writing
a header of the form:

> #+begin_src emacs-lisp :var x="foo" :var y=test3(x)

where x would be given by the call to the block, and y would only be
used internally.

Thanks,

Alan