From mboxrd@z Thu Jan  1 00:00:00 1970
From: Christian Moe <mail@christianmoe.com>
Subject: Re: spreadsheet, generate a column beg end
Date: Tue, 25 Mar 2014 23:30:15 +0100
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To: Uwe Brauer <oub@mat.ucm.es>
Cc: emacs-orgmode@gnu.org


Hi,

Here's one way to do it, applied to an example that takes less space:
With ten rows, say we want to count down from 365 to 358 in the middle
of the middle column ($2), leaving an empty row on top and bottom (@1
and @10).

Set the value of @2$2 to 365, either manually or (as below) in the table
formula. Then set the rest of the range from rows @3 down to @9 to
decrement by one from the cell above (@-1):

|   |     |   |
|   | 365 |   |
|   | 364 |   |
|   | 363 |   |
|   | 362 |   |
|   | 361 |   |
|   | 360 |   |
|   | 359 |   |
|   | 358 |   |
|   |     |   |
#+TBLFM: @2$2=365::@3$2..@9$2=@-1-1

Yours,
Christian

Uwe Brauer writes:

> Hello
>
> In most spreadsheets I know, it is possible to generate easily a column
> say starting in 365 ending in 23.[1] 
>
> Is there any way to do this in the org spreadsheet, without a  loop?
>
> thanks
>
> Uwe Brauer 
>
> Footnotes:
> [1]  (Or in matlab without a loop)