* spreadsheet, generate a column beg end
@ 2014-03-25 19:08 Uwe Brauer
2014-03-25 22:30 ` Christian Moe
0 siblings, 1 reply; 2+ messages in thread
From: Uwe Brauer @ 2014-03-25 19:08 UTC (permalink / raw)
To: emacs-orgmode
Hello
In most spreadsheets I know, it is possible to generate easily a column
say starting in 365 ending in 23.[1]
Is there any way to do this in the org spreadsheet, without a loop?
thanks
Uwe Brauer
Footnotes:
[1] (Or in matlab without a loop)
^ permalink raw reply [flat|nested] 2+ messages in thread
* Re: spreadsheet, generate a column beg end
2014-03-25 19:08 spreadsheet, generate a column beg end Uwe Brauer
@ 2014-03-25 22:30 ` Christian Moe
0 siblings, 0 replies; 2+ messages in thread
From: Christian Moe @ 2014-03-25 22:30 UTC (permalink / raw)
To: Uwe Brauer; +Cc: emacs-orgmode
Hi,
Here's one way to do it, applied to an example that takes less space:
With ten rows, say we want to count down from 365 to 358 in the middle
of the middle column ($2), leaving an empty row on top and bottom (@1
and @10).
Set the value of @2$2 to 365, either manually or (as below) in the table
formula. Then set the rest of the range from rows @3 down to @9 to
decrement by one from the cell above (@-1):
| | | |
| | 365 | |
| | 364 | |
| | 363 | |
| | 362 | |
| | 361 | |
| | 360 | |
| | 359 | |
| | 358 | |
| | | |
#+TBLFM: @2$2=365::@3$2..@9$2=@-1-1
Yours,
Christian
Uwe Brauer writes:
> Hello
>
> In most spreadsheets I know, it is possible to generate easily a column
> say starting in 365 ending in 23.[1]
>
> Is there any way to do this in the org spreadsheet, without a loop?
>
> thanks
>
> Uwe Brauer
>
> Footnotes:
> [1] (Or in matlab without a loop)
^ permalink raw reply [flat|nested] 2+ messages in thread
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