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From: Alan Schmitt <alan.schmitt@polytechnique.org>
To: Eric Schulte <schulte.eric@gmail.com>
Cc: emacs-orgmode <emacs-orgmode@gnu.org>
Subject: Re: How do I chain babel blocks with arguments?
Date: Tue, 22 Apr 2014 14:47:38 +0200	[thread overview]
Message-ID: <m261m17cph.fsf@polytechnique.org> (raw)
In-Reply-To: <87sip5ha70.fsf@gmail.com> (Eric Schulte's message of "Tue, 22 Apr 2014 07:30:39 -0400")

Hi Eric,

On 2014-04-22 13:30, Eric Schulte <schulte.eric@gmail.com> writes:

> Sorry, that's because the "x" should be "z".  See the following.
>
> #+name: z
> : "bar"
> #+name: test3
> #+begin_src emacs-lisp :var x="foo"
> x
> #+end_src
>
> #+RESULTS: test3
> : foo
>
> #+name:test4
> #+begin_src emacs-lisp :var y=test3(x=z)
> y
> #+end_src
>
> #+results: test4
> : "bar"
>
> #+call: test4(y="BAZ")
>
> #+RESULTS:
> : BAZ

I'm afraid I'm not being clear: I want to use the result of `test3' in
the computation done to test4. Intuitively, I want test4 to be something
like: "(lambda (x) (... (test3 x) ...))". This is why I was writing
a header of the form:

> #+begin_src emacs-lisp :var x="foo" :var y=test3(x)

where x would be given by the call to the block, and y would only be
used internally.

Thanks,

Alan

next prev parent reply	other threads:[~2014-04-22 12:48 UTC|newest]

Thread overview: 14+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2014-04-16 17:04 How do I chain babel blocks with arguments? Alan Schmitt
2014-04-16 20:49 ` Charles Berry
2014-04-17 10:11   ` Alan Schmitt
2014-04-17 10:24     ` Thorsten Jolitz
2014-04-17 11:37       ` Alan Schmitt
2014-04-17  5:42 ` Eric Schulte
2014-04-18  6:43   ` Alan Schmitt
2014-04-20  1:41     ` Eric Schulte
2014-04-20  3:33       ` Xebar Saram
2014-04-21  1:22         ` Eric Schulte
2014-04-22  6:53       ` Alan Schmitt
2014-04-22 11:30         ` Eric Schulte
2014-04-22 12:47           ` Alan Schmitt [this message]
2014-04-24  1:16             ` Eric Schulte

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