Hi,
I've been looking through the manual to get more familiar with Babel and using source code in general. Below is a simple example, which I'm not sure is working as intended.
#+tblname: example-table
| 1 | a |
| 2 | b |
| 3 | c |
| 4 | d |
#+begin_src emacs-lisp :var data=example-table[-3,1] :results value raw
data
#+end_src
Upon =C-c C-c= this produces the expected result:
#+results:
b
=C-c C-c= /again/, however, results in:
#+results:
b
b
In other words, the default results handling of =replace= appears to not work with a =raw= results type. I tried explicitly adding the handling via a =:results value raw replace= header argument but again this didn't seem to fix things.
Is this what is intended for the =raw= type of results - no replacement effect at all - or is this a bug?
Chris