Hi,

I've been looking through the manual to get more familiar with Babel and
using source code in general.  Below is a simple example, which I'm not sure
is working as intended.

#+tblname:
example-table
| 1 | a
|
| 2 | b
|
| 3 | c
|
| 4 | d
|


#+begin_src emacs-lisp :var data=example-table[-3,1] :results value raw

data

#+end_src


Upon =C-c C-c= this produces the expected result:

#+results:

b

=C-c C-c= /again/, however, results in:

#+results:

b

b

In other words, the default results handling of =replace= appears to not
work with a =raw= results type.  I tried explicitly adding the handling via
a =:results value raw replace= header argument but again this didn't seem to
fix things.

Is this what is intended for the =raw= type of results - no replacement
effect at all - or is this a bug?

Chris