From: "Göktuğ Kayaalp" <self@gkayaalp.com>
To: joakim@verona.se
Cc: emacs-orgmode <emacs-orgmode@gnu.org>
Subject: Re: How can I call the exporter from function?
Date: Mon, 26 Oct 2015 15:18:04 +0200 [thread overview]
Message-ID: <87ziz5n4z7.fsf@gkayaalp.com> (raw)
In-Reply-To: <m3ziz6vgzu.fsf@exodia.verona.se> (joakim@verona.se's message of "Sun, 25 Oct 2015 21:19:01 +0100")
On Sun, Oct 25 2015 at 10:19:01 pm EET, joakim@verona.se wrote:
> I want to call the exporter in a certain way, so I don't have to type
> the same options every time.
>
> Basically I want to do first this:
> (re-search-backward "^\\*\\* ")
> (org-mark-subtree)
>
> Then I want to export the marked subtree as odt.
See the docstring of `org-odt-export-to-odt'. Its second argument is
SUBTREEP, if T, only the subtree under the point is exported. So a call
like:
(org-odt-export-to-odt nil t)
Would sort your problem out.
>
> With command keys it becomes something like:
> c-c c-e c-s o o
>
> ... If I remember correctly. In this case I would rather do
>
> m-x my-own-canned-exporter
>
> I tried following the exporting dispatcher function but got lost in the
> wilderness. Does anyone have a suggestion?
--
İ. Göktuğ Kayaalp.
http://gkayaalp.com/
prev parent reply other threads:[~2015-10-26 13:07 UTC|newest]
Thread overview: 2+ messages / expand[flat|nested] mbox.gz Atom feed top
2015-10-25 20:19 How can I call the exporter from function? joakim
2015-10-26 13:18 ` Göktuğ Kayaalp [this message]
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