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From: Nick Dokos <ndokos@gmail.com>
To: emacs-orgmode@gnu.org
Subject: Re: Why does evaluating a piece of Elisp code seemingly not expand	a macro?
Date: Fri, 15 Jan 2016 17:06:05 -0500	[thread overview]
Message-ID: <87y4bq4hwy.fsf@alphaville.usersys.redhat.com> (raw)
In-Reply-To: 87pox2mtuy.fsf@turing.flintfam.org

swflint@flintfam.org (Samuel W. Flint) writes:

>>>>>> Marcin Borkowski writes:
>
> MB> This piece of code: #+BEGIN_SRC elisp :results value verbatim
> MB> :exports both (defmacro forty-two () (* 6 7))
>
> That is not a macro.  That's a function.  The return value of a macro
> (the result of the last expression in the implicit progn) needs to be a
> (quasi-)quoted expression.
>

Not so. 

> This macro simply evaluates to 42.  This should be a function.
>
Maybe it should be a function, but it *is* a macro:

--8<---------------cut here---------------start------------->8---
(defmacro forty-two () (* 6 7))
==> forty-two
(symbol-function 'forty-two)
==> (macro lambda nil (* 6 7))
--8<---------------cut here---------------end--------------->8---


> If you want a macro, you could have:
>
> #+BEGIN_SRC: emacs-lisp
>   (defmacro forty-two ()
>             '(* 6 7))
> #+END_SRC
>

That's a different macro:

--8<---------------cut here---------------start------------->8---
(defmacro forty-two () '(* 6 7))
==> forty-two
(symbol-function 'forty-two)
==> (macro lambda nil (quote (* 6 7)))
--8<---------------cut here---------------end--------------->8---

--
Nick

  reply	other threads:[~2016-01-15 22:06 UTC|newest]

Thread overview: 9+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2016-01-15 10:08 Why does evaluating a piece of Elisp code seemingly not expand a macro? Marcin Borkowski
2016-01-15 10:57 ` Oleh Krehel
2016-01-17 22:56   ` Marcin Borkowski
2016-01-18 13:54     ` Stefan Monnier
2016-01-18 20:03       ` Marcin Borkowski
2016-01-18 20:19         ` Stefan Monnier
2016-01-15 21:10 ` Samuel W. Flint
2016-01-15 22:06   ` Nick Dokos [this message]
2016-01-15 22:24   ` Marcin Borkowski

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