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From: "Juan Manuel Macías" <maciaschain@posteo.net>
To: Uwe Brauer <oub@mat.ucm.es>
Cc: orgmode <emacs-orgmode@gnu.org>
Subject: Re: how to export (latex) a image without using figure
Date: Sun, 04 Apr 2021 13:17:28 +0200	[thread overview]
Message-ID: <87pmza2t9z.fsf@posteo.net> (raw)
In-Reply-To: <87blau8hoh.fsf@mat.ucm.es> (Uwe Brauer's message of "Sun, 04 Apr 2021 12:31:26 +0200")

Hi Uwe,


#+ATTR_LaTeX: :float nil
#+CAPTION: La función  La función  $x^2  e^{-\alpha x} = \frac{1}{\alpha}$, $\alpha=-\ln(1-p)$  con $p=0.01$  con $p=0.3$

Best regards,

Juan Manuel 

Uwe Brauer writes:

> Hi 
> Currently 
> #+CAPTION: La función  La función  $x^2  e^{-\alpha x} = \frac{1}{\alpha}$, $\alpha=-\ln(1-p)$  con $p=0.01$  con $p=0.3$
> #+NAME:   fig:plotcalor23
> [[./images/dfp_03.png]]
> Gets translated to 
> \begin{figure}[htbp]
> \centering
> \includegraphics[width=.9\linewidth]{./images/dfp_03.png}
> \caption{\label{fig:plotcalor23}La función  La función  \(x^2  e^{-\alpha x} = \frac{1}{\alpha}\), \(\alpha=-\ln(1-p)\)  con \(p=0.01\)  con \(p=0.3\)}
> \end{figure}
> For reasons that needs a longer explanation I would need.
> \includegraphics[width=.9\linewidth]{./images/dfp_03.png}
> \captionof{figure}{\label{fig:plotcalor23}La función  La función  \(x^2  e^{-\alpha x} = \frac{1}{\alpha}\), \(\alpha=-\ln(1-p)\)  con \(p=0.01\)  con \(p=0.3\)}
> How can this be achieved?
> Thanks 
> Uwe Brauer 

  reply	other threads:[~2021-04-04 11:18 UTC|newest]

Thread overview: 3+ messages / expand[flat|nested]  mbox.gz  Atom feed  top
2021-04-04 10:31 Uwe Brauer
2021-04-04 11:17 ` Juan Manuel Macías [this message]
2021-04-04 11:33   ` Uwe Brauer

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