Hi, thank you for your answer.

Your solution is OK but only for the example I gave (2 or 3 results). In practice I have about 10 results and the number of them may be variable...
Furthermore :vars does not work on my version (I must use :var x=A :var y=B)...

Ta.
Thierry
  
Hello,

>/  I have somethink like that/
>
>/  #+call: gen(A)/
>/  #+results: A/
>/  : 10/
>
>/  #+call: gen(B)/
>/  #+results: B/
>/  : 20/
>
>/  Is there a simple mean to aggregate the results in a table, i.e to get/
>/  | A | 10 |/
>/  | B | 20 |/
>
>/  I think some lisp can do that but as a beginner... but as I want to/
>/  learn you can suggest a somewhat complicated solution or a simple idea./
>/  Thanks./

you could define a 3rd block C that takes the results from block A and B
as variable via :vars x=A y=B (A and B must be named blocks for this,
use a #+NAME: A line) and then do (list A x B y) in block C and use the
:results format that outputs a list as a table (often it is the default,
otherwise try :results table or so).

-- 
cheers,
Thorsten