# json

> \begin{equation} > x=\sqrt{b} > \end{equation} > >> If \(a^2=b\) and \( b=2 \), then the solution must be > either $$ a=+\sqrt{2} $$ or \[ a=-\sqrt{2} \]. >

>
> # json

> \begin{equation}
> x=\sqrt{b}
> \end{equation}
>
>

>
>
>
> Thanks!
> Russell
>
> > If \(a^2=b\) and \( b=2 \), then the solution must be > either $$ a=+\sqrt{2} $$ or \[ a=-\sqrt{2} \]. >

>