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* Re: Docs submitted (really #')
       [not found] <E1LXHgb-00059Z-Tw@box188.bluehost.com>
@ 2009-02-11 16:41 ` Robert Goldman
  0 siblings, 0 replies; only message in thread
From: Robert Goldman @ 2009-02-11 16:41 UTC (permalink / raw)
  To: emacs-orgmode

> Date: Wed, 11 Feb 2009 09:58:43 -0500
> From: Bernt Hansen <bernt@norang.ca>
> Subject: [Orgmode] Re: Docs submitted
> To: Carsten Dominik <dominik@science.uva.nl>
> Cc: emacs-orgmode@gnu.org, "Tom Breton \(Tehom\)" <tehom@panix.com>
> Message-ID: <87fxilggv0.fsf@gollum.intra.norang.ca>
> Content-Type: text/plain; charset=us-ascii
> Carsten Dominik <dominik@science.uva.nl> writes:
>> On Feb 11, 2009, at 2:08 AM, Tom Breton (Tehom) wrote:
>>> (eval-after-load 'org
>>>  '(progn
>>> ;;^--HERE.
>>>     (add-to-list 'org-todo-setup-filter-hook
>>> 		  #'org-choose-setup-filter)
>>>     (add-to-list 'org-todo-get-default-hook
>>> 		  #'org-choose-get-default-mark)
>>>     (add-to-list 'org-trigger-hook
>>> 		  #'org-choose-keep-sensible)
>>>     (add-to-list 'org-todo-interpretation-widgets
>>> 		  '(:tag "Choose   (to record decisions)" choose)
>>> 		  'append)
>>>   ))
>> Hi Tom,
>> maybe you can educate me:  I have never understood what the "#" does
>> in code like the one you have here.  You are using it, so maybe you
>> know?
> As I understand it (from my book on Common Lisp) #'some-function is used
> to quote function names.  'some-function quotes a variable.
> It means "Get me the function with the following name" - without the #',
> Lisp would treat some-function as the name of a variable and look up the
> value of the variable, not the function.

In Common Lisp, #' is a reader macro that is an abbreviation for
function.  So #'foo is read as (function foo).

I'm not at all sure what #' means in elisp, which is not the same
programming language.  A quick peek at the Elisp info file didn't find
reader macros anywhere in there.

AFAIK for defining hooks a symbol will be interpreted as a function
name, won't it?  So replacing all of the #'s with 's above would work,
wouldn't it?


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