From: "Peter Westlake" <peter.westlake@pobox.com>
To: Carsten Dominik <dominik@uva.nl>
Cc: emacs-org list <emacs-orgmode@gnu.org>
Subject: Re: OT: Python help
Date: Tue, 20 Jul 2010 14:08:32 +0100 [thread overview]
Message-ID: <1279631312.15948.1385772637@webmail.messagingengine.com> (raw)
In-Reply-To: <AANLkTimR2R2jH8Bz5NStX6_akzzghWZ5-_HQtk8E8D1E@mail.gmail.com>
On Tue, 20 Jul 2010 16:58 +0530, "Puneeth" <punchagan@gmail.com> wrote:
> On Tue, Jul 20, 2010 at 4:50 PM, Puneeth <punchagan@gmail.com> wrote:
> > On Tue, Jul 20, 2010 at 4:43 PM, Carsten Dominik <dominik@uva.nl> wrote:
> >> Please show me the full line of code, I am currently editing a python script
> >> without any knowledge of python...
> >
> > my_string = "Hello\nWorld"
> > my_new_string = my_string.replace("\n", "\n> ")
>
> Sorry, this code (obviously) doesn't prepend ">" to the first line
> Add this line to do that.
>
> my_new_string = "> " + my_new_string
Here's a Pythonic way to do it, tested:
import re
my_string = "Hello\nWorld"
pattern = re.compile('^',re.MULTILINE)
my_new_string = re.sub(pattern, '> ', my_string)
This still might not be quite right, as it will turn "Hello\nWorld\n"
into "> Hello\n> World\n> ". Avoid that by using a negative lookahead
for the end of the string:
my_string = "Hello\n\nWorld\n"
pattern = re.compile('^(?!\Z)',re.MULTILINE)
my_new_string = re.sub(pattern, '> ', my_string)
print my_new_string
gives:
> Hello
>
> World
Peter.
next prev parent reply other threads:[~2010-07-20 13:17 UTC|newest]
Thread overview: 10+ messages / expand[flat|nested] mbox.gz Atom feed top
2010-07-20 10:47 OT: Python help Carsten Dominik
2010-07-20 11:03 ` Giovanni Ridolfi
2010-07-20 11:13 ` Carsten Dominik
2010-07-20 11:20 ` Puneeth
2010-07-20 11:25 ` Carsten Dominik
2010-07-20 11:28 ` Puneeth
2010-07-20 13:08 ` Peter Westlake [this message]
2010-07-20 13:12 ` Carsten Dominik
2010-07-20 18:03 ` Xiao-Yong Jin
2010-07-20 11:25 ` Giovanni Ridolfi
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